Does the existence of soft Goldstone mode makes a topological superfluid unstable?

When people talk about topological order and Majorana fermions in a BCS superfluid, do they admit the existence of a massless Goldstone mode? (As I’ve heard that soft Goldstone mode always exists in superfluid)

If this is the case, it would mean that the topological order is unstable. Say in 1D case, we have two degenerate ground states due to unpaired Majorana edge modes $|G_{1,2}rangle$. The nonlocal nature of Majorana guarantees that any local perturbation cannot either split their energy or make a transition between them. However, if the Goldstone mode creation operator is given by $B^dagger_{k}$, an arbitrarily small perturbation $H’=B_k+B^dagger_{k}$ would induce a transition from the ground state to an excited state, destroying the topologically-protected qubit.