Dimensional regularization of Electron self-energy from Ryder's book

I am Studying Electron self-energy using Ryder’s textbook, In page 334 we can see

Defining $k’=k-pz$ and avoiding the term linear in $k’$(because it integrates to zero) gives
begin{equation}
Sigma(p)=-ie^2mu^{4-d}int_0^1dzgamma_mu({not} p-{not}p z+m)gamma^muintfrac{d^dk’}{(2pi)^d}frac{1}{[k’^2-m^2z+p^2z(1-z)]^2}.label{r2.7}end{equation}
[…] This integral is performed with the help of equation (9A.5),
giving
begin{equation}
Sigma(p)=mu^{4-d}e^2frac{Gamma(2-frac{d}{2})}{(4pi)^{d/2}}int_0^1dzgamma_mu[{not}p(1-z)+m]gamma^nu[-m^2z+p^2z(1-z)]^{d/2-2}.
end{equation}

The equation 9A.5 is
begin{equation}
intfrac{d^dp}{(p^2+2pq-m^2)^{alpha}}=(-1)^{d/2}imathpi^{d/2}frac{Gammaleft(alpha-frac{d}{2}right)}{Gamma(alpha)}frac{1}{[-q^2-m^2]^{alpha-d/2}} .tag{9A.5}
end{equation}
I don’t understand how he applied this integral (9A.5) to obtain the result
begin{equation}
Sigma(p)=mu^{4-d}e^2frac{Gamma(2-frac{d}{2})}{(4pi)^{d/2}}int_0^1dzgamma_mu[{not}p(1-z)+m]gamma^nu[-m^2z+p^2z(1-z)]^{d/2-2}.
end{equation} please help me to get an idea.