Charge in the each capacitor when connected in parallel

It is the sum of charge on all 3 capacitors. This is because the charge on a single ideal capacitor only depends on the voltage applied across it. When wired in parallel, each capacitor gets the same voltage. The charge on one of them is then independent of the others being present, so the total charge is $Q=V (A+B+C)$.

Capacitors in parallel have the same voltage, since you know the following relation

$$Q=CV$$

One can write down $Q_{total}$ based on our initial statement aka $V_{total}=V$ where $V$ is the voltage through each capacitor

$$Q_{total} = C_{total}V_{total}= C_A V+C_B V+C_C V = V( C_A +C_B +C_C) $$

Where $C_i$ stands for different capacitance $i=A, B, C$. After simplifying the voltages you get the parallel capacitance relation as

$$C_{total}= C_A +C_B +C_C $$

For the total charge, check the equation before the last one