Physics Asked on March 25, 2021
I have no background in thermodynamics or fluid dynamics, so please bear with me. Refer to the following figure:
A working fluid with a flow rate of $1~kg/s$ enters a heater at a pressure of $1~MPa$ and temperature $150~^circ C$, which raises its temperatures to $300~^circ C$. It then enters a turbine, does work, loses pressure and temperature, and exits at $0.5~MPa$ and $200~^circ C$ at the same flow rate. The bypass valve’s purpose is to control the work output of the turbine by bypassing some of the working fluid from the inlet stream directly to the outlet stream. Suppose that we’re free to make all the “simplifying assumptions” for this problem. Suppose also that initially the opening fraction of the bypass valve is $0%$ i.e., the valve is fully closed. My questions are:
Some questions might seem redundant, but I listed them to get a thorough response, for clarity and understanding. Also, all the numbers are arbitrary and any unreported quantities could be assumed. Thank you.
I can answer the question of how looks like a viscous, heat-conducting compressible gas flows in a 2D pipe with a heater and a turbine. I use my code tested on several problems. First, consider the case without bypass. Figure 1 shows the distribution of velocity (left), pressure (center) and temperature (right). From these data it can be seen that the heated gas enters the turbine which rotates at a constant angular velocity.
In Figure 2 shown the distribution of velocity (left), pressure (center) and temperature (right) in a system with bybass. This animation shows how the turbine is filled. In the beginning we can see how the turbine rotates. Now we can compare the parameters of pressure and gas flow with a closed (upper row) and open (lower row) valve. In Fig. 4 shows the distribution of pressure (left), $rho u$ (center) and $int {rho udy}$ (right) in lower (1) and upper pipe (2).
Answered by Alex Trounev on March 25, 2021
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