Physics Asked by Mesoscopic C on May 13, 2021
So, in doing some numerical computations in QFT, I’ve run into the following Wigner $6j$-Symbol:
$$
left{
begin{array}{ccc}
x & J_1 & J_2
frac{N}{2} & frac{N}{2} & frac{N}{2}
end{array}
right}.
$$
In the regime where $x ll J_1,J_2,N$ and $J_1 approx J_2 approx N$, and $N$ is large. I would like to know if there is an asymptotic formula for such a symbol, or if one can be derived. Using symmetries we can get
$$
left{
begin{array}{ccc}
x & frac{1}{2} left(J_1+J_2right) & frac{1}{2} left(J_1+J_2right)
frac{N}{2} & frac{1}{2} left(N+J_1-J_2right) & frac{1}{2} left(N-J_1+J_2right)
end{array}
right}.
$$
Perhaps this could help, I’m really not sure.
The source for this is the book of Varshalovich et al, Quantum Theory of angular momentum. In section 9.8 one can find the following: $$ left{begin{array}{ccc} a&b&c d+R&e+R& f+Rend{array}right} approx frac{(-1)^{a+b+d+e}}{sqrt{2R(2c+1)}}C^{cgamma}_{aalpha;bbeta} $$ where $C^{cgamma}_{aalpha;bbeta}$ is a Clebsch Gordan coefficient, and where $alpha=f-e, beta=d-f, gamma=d-e$. This expression is valid in the limit where $Rgg 1$.
(I have never personally used this but with a few simple test using Mathematica gives a pretty good estimate. For instance, with $(a,b,c,d,e,f)=(3,3,2,2,4,4)$ and $R=75$, the $6japprox -0.01763$ while the approximate expression gives $-0.01781$.)
Answered by ZeroTheHero on May 13, 2021
For the asymptotic behavior of the Wigner 6j-Symbol when all the coefficients but one grow, you can use the Edmonds formula. In your case it reads as:
$$ leftlbracebegin{matrix} x & J_1 & J_2 frac{N}{2} & frac{N}{2} & frac{N}{2}end{matrix}rightrbrace approx dfrac{(-1)^{J_2+N+x}}{sqrt{(2J_2+1)(N+1)}}d^x_{J1-J2, 0}(phi), $$
where $d^x_{J1-J2, 0}(phi)$ is the small Wigner d-matrix and
$$ cos(phi)=frac{1}{2}sqrt{dfrac{J_1(J_1+1)}{N/2(N/2+1)}}. $$
Here it is a good reference https://aip.scitation.org/doi/10.1063/1.532474 .
Answered by Milo Viviani on May 13, 2021
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