Mathematics Asked by Ethan Chan on January 19, 2021
I’m currently stuck on this inequality problem:
So far, I tried to prove it by using a proof by contrapositive, but that doesn’t seem to work. Could I get a hint on how to proceed?
Not really just a hint, however you can stop reading after the line below and consider completing yourself. $$frac{bc-ad}{bd} = frac{c}d-frac{a}b = left(frac{c}d-frac{p}q right) + left(frac{p}q-frac{a}b right)geqslant frac1{dq}+frac1{bq}$$ as each term in the brackets is positive.
BTW, the "lowest" such fraction is called the mediant $= dfrac{a+c}{b+d}$.
Correct answer by Macavity on January 19, 2021
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