Probability of Normal Distribution

Let’s say that 10 sumo wrestlers were to squeeze into an elevator that could only hold a max capacity of 2300 pounds. Let’s say that the weight of the sumo wrestlers is normally distributed with a mean of 220 lbs and a standard deviation of 25 pounds, what’s the probability that the elevator is past it’s max cap.?

So far I have that

μ = 220
σ = 25

I thought of (2300-2200)/25
= 4 (but that doesn’t seem right. )

and something like P {X > 2300} = Pr {Z>what apparently 4 would be} = 1 – (something here)

I’m not sure if I’m even doing this problem right.