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Lebesgue measure of boundary of an open set.

Mathematics Asked by Santanu Debnath on December 23, 2021

Let $g$ be a continuous function on $mathbb{R}^n$ and $$O={xin mathbb{R}^n:g(x)neq 0}.$$
Is it true that Lebesgue measure of Boundary of $O$ always zero?

One Answer

In $Bbb R$ let $C$ be a fat Cantor set. This is constructed in a similar way to the usual Cantor set, but the removed open intervals shrink quickly enough in length to ensure than $C$ has non-zero Lebesgue measure.

Let $O$ be the complement of $C$. The boundary of $O$ is the boundary of $C$ which is $C$ itself. The boundary of $O$ has non-zero measure.

If we define $g(x)=text{distance}(x,C)$ then $g$ is continuous, and $O$ is the set of $x$ with $g(x)ne0$.

Answered by Angina Seng on December 23, 2021

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