Mathematics Asked by Sam Blitz on February 20, 2021
For reasons that are completely absurd, I’m interested in whether such a function $f$ (as briefly described in the title) exists:
$f$ is smooth on the interval $(0,1)$.
$f(0) = 1$
$f(1) = 0$
$f$ is monotonically decreasing on the interval $(0,1)$
$d/dx (ln f) < 0$ and is monotonically increasing on the interval $(0,1)$.
If possible, $d/dx (ln f) to 0$ as $x to 1$. But this condition is not a requirement.
I suspect that such a function does not exist, because as the function approaches zero, its logarithmic derivative will diverge – that is, unless it’s (standard) derivative goes as $f(x) g(x)$ where $g(x)$ goes to zero in the limit where $x to 1$.
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