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Consider the sequence where $a_1>0$, $ka_n>a_{n+1}$ and $0<k<1$. Can we say it converges?

Mathematics Asked by oek Cafu on December 3, 2021

I could get that

$a_1>k^n a_1 > a_{n+1}$ and therefore $0geqlim a_n$

But I can’t find a lower bound for the squeeze theorem or something about monotonicity.

Any idea about this?

One Answer

Not without additional conditions (e.g. if $forall n,(a_nge 0),$).

For example if $k=1/2$ and $a_1=1$ and $a_n=-n$ for $n>1.$

Answered by DanielWainfleet on December 3, 2021

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