Mathematics Asked by user1333549 on November 9, 2021
Let $X$ be a set. How many $sigma$-algebras of subsets of $X$ contain exactly $m$ elements?
Any hints for how to begin a solution to this problem are greatly appreciated.
My initial approach is as follows:
Let $|X| = n$, then $|P(X)| = 2^n$
Thus our count is given by
$binom{2^n}{m}$
We have no information as to the cardinality of $X$.
Algebras (and thus $sigma$-algebras) of subsets of a finite set correspond to partitions of the set. If $P = {P_1, ldots, P_k}$ is a partition of $X$, i.e. disjoint nonempty subsets whose union is $X$, then you get an algebra consisting of the $2^k$ unions of subsets of $P$. So if $m = 2^k$, the number of algebras of subsets of $X$ is the number of partitions of $X$ into $k$ parts. If $m$ is not a power of $2$, there are no algebras with cardinality $m$.
Answered by Robert Israel on November 9, 2021
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