Mathematica Asked on July 24, 2021
I have this data for four quantities measured in different temperatures:
data = {{729, 656, 2156, 2035}, {761, 677, 2178, 2060}, {952, 856,
2651, 2465}, {888, 796, 2311, 2139}, {747, 645, 1807, 1658}, {863,
737, 1975, 1817}, {844, 734, 1841, 1654}, {705, 602, 1466,
1305}, {788, 686, 1491, 1303}, {927, 779, 1732, 1547}, {910, 742,
1616, 1429}};
N[Correlation[data], 2]
There are 11 temperature measurements and 4 quantities measured at the same time. The correlation function gives as output:
{{1.0, 0.95, 0.36, 0.30}, {0.95, 1.0, 0.59, 0.54}, {0.36, 0.59, 1.0,
1.0}, {0.30, 0.54, 1.0, 1.0}}
As I understand, the output of Correlation[] gives a matrix of the Pearson coefficient for each element in the data. Is that correct? Does it mean that the first and last entries in each data point have a correlation of 0.30?
data = {
{729, 656, 2156, 2035}, {761, 677, 2178, 2060},
{952, 856, 2651, 2465}, {888, 796, 2311, 2139},
{747, 645, 1807, 1658}, {863, 737, 1975, 1817},
{844, 734, 1841, 1654}, {705, 602, 1466, 1305},
{788, 686, 1491, 1303}, {927, 779, 1732, 1547},
{910, 742, 1616, 1429}};
matrix = N[Correlation[data], 4];
rules = (N[Correlation @@
Transpose[data[[All, #]]], 4] -> #) & /@ Tuples[Range[4], {2}];
{1,1} {1,2} {1,3} {1,4} {1,2} {1,1} {2,3} {2,4} {1,3} {2,3} {1,1} {3,4} {1,4} {2,4} {3,4} {1,1}
This grid shows which columns correspond to the correlations in the matrix.
E.g. Grid[matrix]
1.000 0.9504 0.3553 0.3012 0.9504 1.000 0.5918 0.5411 0.3553 0.5918 1.000 0.9977 0.3012 0.5411 0.9977 1.000
0.3012 corresponds to the correlation of columns 1 & 4
N[Correlation @@ Transpose[data[[All, {1, 4}]]], 4]
0.3012
Answered by Chris Degnen on July 24, 2021
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