Relative error with bands plot

Question

I have 2 sets of data imported from excel file, Let say
A = 20
21
22
...
30A
B= 0
1
2
3
...
10
I want to plot A with a relative error of 10%
errordataA= Around[A,Scaled[.1]]

But output was "Around[A, Scaled[0.1]]" not "Around[2+-10%]".
Then I want to create a plot with B.
ListPlot[
 {A,
  B
    }
   IntervalMarkers -> "Bands",
 Sequence[PlotTheme -> "Scientific",
  PlotRangePadding -> {Automatic, Scaled[0.15]}]
 ]

Since the code can't read set A data so the graph does not show.
How can I fix this one?

MarcoB · Answer

The Around expression you mention seems to work fine for me:
a = Around[Range[20, 30], Scaled[0.1]]

(* Out: {Around[20., 2.], Around[21., 2.1], Around[22., 2.2], 
         Around[23., 2.3], Around[24., 2.4], Around[25., 2.5], 
         Around[26., 2.6], Around[27., 2.7], 
         Around[28., 2.8], Around[29., 2.9], 
         Around[30., 3.]} *)

From there, I think you might want to plot a vs. b, i.e. the a values as ordinates and the values as abscissae. If that's what you want, then that works too, but you will want to Transpose the {b, a} set of data:
a = Around[Range[20, 30], Scaled[0.1]]
b = Range[0, 10]

ListPlot[
  Transpose@{b, a},
  IntervalMarkers -> "Bands",
  PlotTheme -> "Scientific",
  PlotRangePadding -> {Automatic, Scaled[0.15]}
]

—-
An alternative interpretation after OP’s comments:
ListPlot[
  {a, b},
  IntervalMarkers -> "Bands",
  PlotTheme -> "Scientific",
  PlotRangePadding -> {Automatic, Scaled[0.15]}
]

Bob Hanlon · Answer

For versions prior to v12
Clear["Global`*"]

Needs["ErrorBarPlots`"] // Quiet

a = {1, 0.1} # & /@ Range[20, 30];

b = Range[0, 10];

ErrorListPlot[{a, b},
 PlotRangePadding -> {Automatic, Scaled[0.1]},
 PlotLegends -> {"a", "b"},
 PlotTheme -> "Scientific"]

Relative error with bands plot

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