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It is known that $f(x)$ has a first-order continuous derivative in a neighborhood of point x = 0 and $f(0) f^{prime}(0) neq 0$. When $h rightarrow 0$,then...
Asked on 09/08/2020
2 answer{x1,y1,x2,y2,x3,y3}={-2.,3.,1.,-1.,4.,0};soln=NSolve[{h^2==a b,a x^2+2 h x y+b y^2+2 f x+2 g y==1,a x1^2+2 h x1 y1+b y1^2+2 f x1+2 g y1==1,a x2^2+2 h x2 y2+b y2^2+2 f x2+2 g y2==1,a...
Asked on 09/06/2020
0 answerI have been using Wolfram Mathematica for about 3 years and never experienced this before. Out of the blue, today it started behaving like this; anytime I try to look...
Asked on 09/06/2020 by PanchoTheMacho
0 answerI have a problem with defining a function and most of time I get confused by Set or = and SetDelayed or :=.I read the help section but I...
Asked on 09/05/2020 by DSaad
2 answerI know that the three eigenvalues of the real third order matrix A are -1, 1, 1, and the eigenvector corresponding to eigenvalue -1 is $(0,1,1)^T$. I want...
Asked on 09/04/2020
1 answerI have faced with problem of not completely correct phase trajectories of ODE, which was produced by StreamPlot. Next following code ends up with this plot: f[x_, y_] =...
Asked on 09/04/2020 by RuD_wow
2 answerI am trying to do some symbolic statistics.Is there a way to get the Domain of a distribution?Like thisDomain[UniformDistribution[]]>> 0<=x<=1Domain[BinomialDistribution[n,p]]>> 0 <= x <= n && x...
Asked on 09/03/2020 by meneken17
1 answerI have a long equation, namely,equ = 4576.66 a[1] Cos[t] + 3.3877 a[1]^3 Cos[t]^3 + 4576.65 a[2] Cos[2 t] + 10.1631 a[1]^2 a[2] Cos[t]^2 Cos[2 t] + 10.1631 a[1]...
Asked on 09/02/2020 by PureLine
1 answerGiven that ${u_n}$ is a monotonically increasing bounded sequence, now I want to judge whether the following sequence converges: $$begin{array}{c}A. sum_{n = 1}^{infty} frac{u_{n}}{n} ...
Asked on 08/31/2020 by Montevideo
1 answerI asked this question on Math stachexchange. The question I have is: Can I use Mathematica to find the (integral points on the following elliptic curve) or can I...
Asked on 08/31/2020
3 answerGet help from others!
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