Mathematica Asked by Kassidy Moy on August 4, 2021
Clear["Global`*"]
areaSides = Pi*r*Sqrt[r^2 + h^2];
areaTop = Pi*r^2;
volume = Pi*r^2*h/3;
cost = 100*volume + 50*areaSides + 25*areaTop;
solh = Solve[volume == 50, h][[1]]
(* {h -> 150/(π r^2)} *)
The radius of the pit in meters is
solr = Solve[{D[cost /. solh, r] == 0, r > 0}, r][[1]] // N
(* {r -> 2.84461} *)
The depth of the pit in meters is
h /. solh /. solr
(* 5.90061 *)
The minimum cost in dollars is
cost /. solh /. solr
(* 8562.48 *)
Verifying,
Minimize[{cost, volume == 50, r > 0, h > 0}, {r, h}] // N
(* {8562.48, {r -> 2.84461, h -> 5.90061}} *)
Answered by Bob Hanlon on August 4, 2021
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