Geographic Information Systems Asked on April 18, 2021
I’m trying to make sense of the CRS definition in QGIS 3.4 for State Plane projections. I believe the datum should be NAD83, but I’m not seeing this in the definition that shows up in QGIS, and I want to find out 1)is this correct, and if so 2) why is the GIS able to use this definition?
For example, for NAD 83 / Massachusetts State Plane Maineland, here is what shows up:
Extent: -73.50, 41.46, -69.86, 42.89
Proj4: +proj=lcc +lat_1=42.68333333333333 +lat_2=41.71666666666667 +lat_0=41 +lon_0=-71.5 +x_0=200000 +y_0=750000 +ellps=GRS80 +towgs84=0,0,0,0,0,0,0 +units=m +no_defs
So GRS80 is specified as the ellipsoid, but I don’t see anything about the datum. Is the ellipsoid enough by itself? What’s going on here?
In order to be well-defined, a datum needs two things:
In the case of NAD83, its reference spheroid is GRS80, and since it is sometimes considered equivalent to WGS84 (depending on the application, a 1-2 meter difference could be considered acceptable), many applications will, by default, set the transformation to zero (in other words, no datum transformation is performed when converting between NAD83 and WGS84).
If we look at the proj string, you can see those two elements, hence NAD83 is well-defined (at least within the accuracy mentioned earlier) The ellipsoid is mentioned: +ellps=GRS80
and a link to WGS84 is also present: +towgs84=0,0,0,0,0,0,0
. In this case, as you can see, the transformation is set to zero.
Another way to write this with a proj string, is to use the parameter +datum=NAD83
, which explicitly states the datum in use, and in most cases has the same effect as using +ellps=GRS80 +towgs84=0,0,0,0,0,0,0
If your data requires higher accuracy, then it becomes important to know which version of NAD83 is used in order to choose the best transformation to other datums. However, if you are only dealing with data in NAD83, everything should overlay just fine.
Correct answer by FSimardGIS on April 18, 2021
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