PyQGIS output to specific layer

Question

I have a Python script that I have exported from a QGIS model and I want to specify the layer it creates as output.

If defaultValue=None it outputs 'Reportpmbc': 'Centroids_9c779c9c_4bcc_471b_971e_fbea3bb27c7d', in the log window and a 'Centroids' layer is created in the project.

I want it to create a temporary layer 'Report-PMBC' as below but it won't run.  (“.” files are not supported as outputs for this algorithm)

What am I missing in the statement below? I think I have to create a temporary layer in memory and write to it but I am not sure how to do that.

self.addParameter(QgsProcessingParameterFeatureSink('Reportpmbc', 'Report-PMBC', type=QgsProcessing.TypeVectorPoint, createByDefault=True, defaultValue='Report-PMBC'))

lcoandrade · Answer

Create the variable Report-PMBC in your algorithm like this:

class YourAlg(QgsProcessingAlgorithm):
    Report_PMBC = 'Report-PMBC'

Add the parameter like this in you initAlgorithm method:

self.addParameter(QgsProcessingParameterFeatureSink(
            self.Report-PMBC,
            'Report-PMBC',
            QgsProcessing.TypeVectorPoint))

PyQGIS output to specific layer

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