Engineering Asked by Srijan M.T on June 12, 2021
A man threw a ball with force 10 N to two displacement of 5 m and 10 m.
Work done = 10 × 5 and 10 × 10 = 50 Nm and 100 Nm.
Now, since a = 5, I assumed that after 5 m velocity = 25 [m/s].
Now, when I do K.E f – K.E initial for final work done i.e 50 Nm for now.
So , then K.E final is not equal to work done final.
25 × 25 is not equal to 50 Nm.
Where am I wrong?
The mistake is in your assumption.
Now, since a = 5, I assumed that after 5 m velocity = 25 m/s.
the correct would have been
Now, since a = 5, I assumed that after 5 [s] velocity = 25 m/s.
The way you can calculate it is from the following form of the equation for acceleration:
$$a = u frac{du}{ds}$$
you can obtain that $acdot 5m = frac{u_{out}^2}{2} rightarrow u_{out} = sqrt{2 cdot acdot 5[m]}$.
The rest I leave to you.
Correct answer by NMech on June 12, 2021
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