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How to calculate the required torque for an azimuth/elevation antenna rotator?

Engineering Asked by hjf on January 10, 2021

I want to build an antenna rotator for a 1M dish. How do I calculate the required torque for the motor of the elevation axis?

Here’s a sketch of the problem:
enter image description here

If the “bottom” of the dish is the pivot point, what would be the required torque to rotate the dish around this pivot point? Obviously the motor will have a series of reductions to reach the required torque and speed. The last stage a worm gear with a turn ratio enough to prevent rotation from the antenna weight when no power is being applied.

One Answer

we just do it for gravity and assume 90% efficiency for the gear, or if they have a datasheet look that up.

Regardless of the dish being perforated in certain angles it could act as a wing and create flutter, lift, destructive vibration. So we need to use a light truss to stiffen the dish.

Let's call the dish mass m and its depth H, and assume by just eyeballing the parabola's CG axis is at H*0.45. and say we want the torque $ tau $ to deflect the dish from horizontal to 90 degrees up vertical.

$ tau_{max }= m *0.45H/9*(1/0.9)=0.055mH$

Answered by kamran on January 10, 2021

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