Engineering Asked by hjf on January 10, 2021
I want to build an antenna rotator for a 1M dish. How do I calculate the required torque for the motor of the elevation axis?
Here’s a sketch of the problem:
If the “bottom” of the dish is the pivot point, what would be the required torque to rotate the dish around this pivot point? Obviously the motor will have a series of reductions to reach the required torque and speed. The last stage a worm gear with a turn ratio enough to prevent rotation from the antenna weight when no power is being applied.
we just do it for gravity and assume 90% efficiency for the gear, or if they have a datasheet look that up.
Regardless of the dish being perforated in certain angles it could act as a wing and create flutter, lift, destructive vibration. So we need to use a light truss to stiffen the dish.
Let's call the dish mass m and its depth H, and assume by just eyeballing the parabola's CG axis is at H*0.45. and say we want the torque $ tau $ to deflect the dish from horizontal to 90 degrees up vertical.
$ tau_{max }= m *0.45H/9*(1/0.9)=0.055mH$
Answered by kamran on January 10, 2021
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