Doubt regarding meta-stable and labile region of a supersaturated solution

I have read in a paper that the for formation of new crystals in a solution the energy released due to formation of solid from solution should be more than the energy needed to overcome solid-liquid interactions. As in the meta-stable this is not favorable, no new crystals form in the meta-stable region i.e. low supersaturation state. My doubt is, if it is thermodynamically unfavorable to form new crystals in meta-stable region then why does crystals grow in meta-stable region. In a way, it is also the formation of new crystals.

The exact lines from the text is: “The formation of stable nuclei only happens if the increase in interfacial energy resulting from the formation of a solid{liquid interface is offset by a decrease in energy released by the formation of a (thermodynamically favored) solid. At low supersaturations, the energy required to form a solid{liquid interface is bigger than the energy released upon formation of a cluster which are consequently unstable resulting in a very low nucleation rate. Only when the supersaturation is high enough, i.e. when we enter the labile region, stable solid particles will form.”