Voltage divider homework

You seem to have answered your question in the comment above. It's easy enough to calculate the value for $R_L$ given the voltage and power: $$R_L = V_L^2/P_L = 277.8 kOmega$$ What may have been stumping you is that the problem has an extra degree of freedom; you can choose the value for either $R_1$ or $R_2$ and calculate the other. Your answer above is correct, but a simpler solution can be had if you choose $R_2 = R_L$, then $R_2|| R_L =R_L/2$, and since $V_L$ is $1/3$ of the supplied voltage, the required value of $R_1$ is twice that parallel combination, so $R_1=R_L$ as well.