Electrical Engineering Asked by helpmeplease on December 31, 2021
This is, hopefully, just enough of an answer to get you to figure it out yourself.
As you have realised (indicated in the comments) in the question we are using $ I_L $ which is the peak value of a cosine waveform. The RMS value (required for the power calculation) is $ frac {1}{sqrt 2} I_L $.
Since $ P = I^2R $ we get $ P_L = left (frac {1}{sqrt 2} I_{pk} right )^2 R_L = frac {1}{2} I_{pk}^2 R_L $ as written in the question.
Answered by Transistor on December 31, 2021
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