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Average Power of load conected to an Ideal Transformer

Electrical Engineering Asked by helpmeplease on December 31, 2021

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Where does the 1/2 come from in the power equation?

One Answer

This is, hopefully, just enough of an answer to get you to figure it out yourself.

  • Your voltage is given as a cosine function.
  • What is its peak voltage?
  • What is its RMS voltage?
  • What is the RMS current?
  • What happens when you ...?

As you have realised (indicated in the comments) in the question we are using $ I_L $ which is the peak value of a cosine waveform. The RMS value (required for the power calculation) is $ frac {1}{sqrt 2} I_L $.

Since $ P = I^2R $ we get $ P_L = left (frac {1}{sqrt 2} I_{pk} right )^2 R_L = frac {1}{2} I_{pk}^2 R_L $ as written in the question.

Answered by Transistor on December 31, 2021

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