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MD5 - Chosen Prefix Collision Attack

Cryptography Asked on December 17, 2021

Given 2 messages $m_1$ and $m_2$, in a chosen prefix attack, we want to find $s_1$ and $s_2$ such that:

$text{MD5}(m_1 || s_1) = text{MD5}(m_2 || s_2)$

Are $s_1$ and $s_2$ found by brute force or are there some rule(s) to construct $s_1$ and $s_2$ based on $m_1$ and $m_2$?

One Answer

The answer is due to the Stevens et. al's work ;

They showed that, with an approximately $2^{39}$ calls to the MD5 compression function, it is possible, for any chosen $m_1$ and $m_2$, to construct $s_1$ and $s_2$ such that $$text{MD5} (m_1mathbin|s_1) = text{MD5} (m_2mathbin|s_2)$$

They also gave examples for colliding documents, software integrity checking, etc ...

Answered by kelalaka on December 17, 2021

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