Code Golf Asked by Conor O'Brien on December 21, 2020
The Champernowne constant is a number that is constructed by concatenating the first n
numbers, with n
tending to infinity. It looks something like this:
0.123456789101112131415161718192021222324252627282930...
Now, I will describe to you the Rien number. It can be thought of as a minimization of the Champernowne constant as an integer. I will refer to the Rien number with the first n
digits as Ri(n). This is how to formulate it:
n
natural numbers (the sequence {1,2,3,…}) are concatenated.1..12
would look like 011111223456789
.0
s so that they are significant, whilst keeping the number minimized, resulting in, say, 101111223456789
. This is Ri(n), in this case, Ri(12).Here are some results for Ri(n):
n Ri(n) 1 1 2 12 3 123 7 1234567 9 123456789 10 10123456789 15 101111111223344556789 34 10001111111111111222222222222223333333334444555666777888999 42 100001111111111111122222222222222233333333333333444444455556666777788889999 45 100001111111111111122222222222222233333333333333344444444444555556666777788889999 55 10000011111111111111122222222222222223333333333333333444444444444444455555555555566666777778888899999 100 100000000000111111111111111111112222222222222222222233333333333333333333444444444444444444445555555555555555555566666666666666666666777777777777777777778888888888888888888899999999999999999999 999 100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000011111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999
Objective Given a number 1 ≤ n
< 10000 as input (via arguments, STDIN, or hardcoding if your language does not support conventional input), output/return Ri(n
).
This is a code-golf, so the shortest code in bytes wins. You may use a language that was made after this contest, as long as it was not made for answering this challenge. (Of course, you can use it, if it provides an interesting solution, but mark your answer as non-competing.)
I tested this in IE, so there really shouldn’t be a problem. If there is a problem, there’s an easy solution: get a sane browser.
function min(n) {
var seq = [];
for(var i = 1; i <= n; i++) seq.push(i);
seq = seq.join("").split("").map(Number);
var to;
if(seq.indexOf(1) >= 0) to = seq.splice(seq.indexOf(1), 1);
seq.sort(function(a, b) {
return a - b;
});
if(to) seq = to.concat(seq);
return seq.join("");
}
t.onchange = t.onkeyup = function() {
h.innerHTML = min(this.value)
}
* {
font-family: Consolas, monospace;
}
input {
border: 2px dotted #aaaaaa;
border-radius: 5px;
margin: 10px;
}
<input id="t" type="number">
<div id="h">
The Stack Snippet at the bottom of this post generates the catalog from the answers a) as a list of shortest solution per language and b) as an overall leaderboard.
To make sure that your answer shows up, please start your answer with a headline, using the following Markdown template:
## Language Name, N bytes
where N
is the size of your submission. If you improve your score, you can keep old scores in the headline, by striking them through. For instance:
## Ruby, <s>104</s> <s>101</s> 96 bytes
If there you want to include multiple numbers in your header (e.g. because your score is the sum of two files or you want to list interpreter flag penalties separately), make sure that the actual score is the last number in the header:
## Perl, 43 + 2 (-p flag) = 45 bytes
You can also make the language name a link which will then show up in the snippet:
## [><>](http://esolangs.org/wiki/Fish), 121 bytes
var QUESTION_ID=68685,OVERRIDE_USER=44713;function answersUrl(e){return"https://api.stackexchange.com/2.2/questions/"+QUESTION_ID+"/answers?page="+e+"&pagesize=100&order=desc&sort=creation&site=codegolf&filter="+ANSWER_FILTER}function commentUrl(e,s){return"https://api.stackexchange.com/2.2/answers/"+s.join(";")+"/comments?page="+e+"&pagesize=100&order=desc&sort=creation&site=codegolf&filter="+COMMENT_FILTER}function getAnswers(){jQuery.ajax({url:answersUrl(answer_page++),method:"get",dataType:"jsonp",crossDomain:!0,success:function(e){answers.push.apply(answers,e.items),answers_hash=[],answer_ids=[],e.items.forEach(function(e){e.comments=[];var s=+e.share_link.match(/d+/);answer_ids.push(s),answers_hash[s]=e}),e.has_more||(more_answers=!1),comment_page=1,getComments()}})}function getComments(){jQuery.ajax({url:commentUrl(comment_page++,answer_ids),method:"get",dataType:"jsonp",crossDomain:!0,success:function(e){e.items.forEach(function(e){e.owner.user_id===OVERRIDE_USER&&answers_hash[e.post_id].comments.push(e)}),e.has_more?getComments():more_answers?getAnswers():process()}})}function getAuthorName(e){return e.owner.display_name}function process(){var e=[];answers.forEach(function(s){var r=s.body;s.comments.forEach(function(e){OVERRIDE_REG.test(e.body)&&(r="<h1>"+e.body.replace(OVERRIDE_REG,"")+"</h1>")});var a=r.match(SCORE_REG);a&&e.push({user:getAuthorName(s),size:+a[2],language:a[1],link:s.share_link})}),e.sort(function(e,s){var r=e.size,a=s.size;return r-a});var s={},r=1,a=null,n=1;e.forEach(function(e){e.size!=a&&(n=r),a=e.size,++r;var t=jQuery("#answer-template").html();t=t.replace("{{PLACE}}",n+".").replace("{{NAME}}",e.user).replace("{{LANGUAGE}}",e.language).replace("{{SIZE}}",e.size).replace("{{LINK}}",e.link),t=jQuery(t),jQuery("#answers").append(t);var o=e.language;/<a/.test(o)&&(o=jQuery(o).text()),s[o]=s[o]||{lang:e.language,user:e.user,size:e.size,link:e.link}});var t=[];for(var o in s)s.hasOwnProperty(o)&&t.push(s[o]);t.sort(function(e,s){return e.lang>s.lang?1:e.lang<s.lang?-1:0});for(var c=0;c<t.length;++c){var i=jQuery("#language-template").html(),o=t[c];i=i.replace("{{LANGUAGE}}",o.lang).replace("{{NAME}}",o.user).replace("{{SIZE}}",o.size).replace("{{LINK}}",o.link),i=jQuery(i),jQuery("#languages").append(i)}}var ANSWER_FILTER="!t)IWYnsLAZle2tQ3KqrVveCRJfxcRLe",COMMENT_FILTER="!)Q2B_A2kjfAiU78X(md6BoYk",answers=[],answers_hash,answer_ids,answer_page=1,more_answers=!0,comment_page;getAnswers();var SCORE_REG=/<hd>s*([^n,]*[^s,]),.*?(d+)(?=[^nd<>]*(?:<(?:s>[^n<>]*</s>|[^n<>]+>)[^nd<>]*)*</hd>)/,OVERRIDE_REG=/^Overrides*header:s*/i;
body{text-align:left!important}#answer-list,#language-list{padding:10px;width:290px;float:left}table thead{font-weight:700}table td{padding:5px}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <link rel="stylesheet" type="text/css" href="//cdn.sstatic.net/codegolf/all.css?v=83c949450c8b"> <div id="answer-list"> <h2>Leaderboard</h2> <table class="answer-list"> <thead> <tr><td></td><td>Author</td><td>Language</td><td>Size</td></tr></thead> <tbody id="answers"> </tbody> </table> </div><div id="language-list"> <h2>Winners by Language</h2> <table class="language-list"> <thead> <tr><td>Language</td><td>User</td><td>Score</td></tr></thead> <tbody id="languages"> </tbody> </table> </div><table style="display: none"> <tbody id="answer-template"> <tr><td>{{PLACE}}</td><td>{{NAME}}</td><td>{{LANGUAGE}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr></tbody> </table> <table style="display: none"> <tbody id="language-template"> <tr><td>{{LANGUAGE}}</td><td>{{NAME}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr></tbody> </table>
+1SjktSQ
Makes a list [1, .. , input]
then removes the leading one, joins and sorts, then prepends a 1.
Correct answer by FryAmTheEggman on December 21, 2020
ô ¤¬ñ i1
ô ¤¬ñ i1 :Implicit input of integer
ô :Range [0,input]
¤ :Slice off the first 2 elements
¬ :Join
ñ :Sort
i1 :Prepend 1
Answered by Shaggy on December 21, 2020
Answered by Razetime on December 21, 2020
Thanks to edc65 for 2 bytes
F=
x=>1+[...(g=_=>x>1?x--+g``:_)``].sort().join``
;console.log(F(15))
Answered by l4m2 on December 21, 2020
f(n){char s[++n];int d[10]={0},j=1,k;for(;sprintf(s,"%d",j),j++<n;)for(k=0;s[k];)d[s[k++]-48]++;d[printf("1")]--;for(j=0;j<10;j++)for(k=d[j];k--;putchar(j+48));}
Answered by Jonathan Frech on December 21, 2020
{"1"+Sort!Join[2:_]}
The point-free version is actually 1 byte longer: "1"&`+@Sort@Join@2&`:
. This works as most of the other answers do.
Answered by Conor O'Brien on December 21, 2020
2|>''join sorted'1'+
Try it here! Expects input on TOS. Example on the repl:
> 15
(15)
> 2|>''join sorted'1'+
('101111111223344556789')
2|>''join sorted'1'+
2|> range from 2 to n
''join join by empty string
sorted sort it
'1'+ and prepend a '1'
A more fun version:
{*x:1[1+:yield]x 1-*}!toarr''join sorted'1'+
Expects input as TOS. For example (on the repl):
> 15 (* the input *)
(15)
> {*x:1[1+:yield]x 1-*}!toarr''join sorted'1'+
('101111111223344556789')
>
{*x:1[1+:yield]x 1-*}!toarr''join sorted'1'+
{*x:1[1+:yield]x 1-*} generator function that...
x: given x
1 pushes 1
[ ]x 1-* and executes the inside (x-1) times:
1+ adds 1 to the TOS (initially 1);
2 is the first value yielded
:yield and yields it for the generator
! initialize this generator with TOS
toarr exhaust generator into an array
''join join by empty strings
sorted sort the values
'1'+ prepend '1'.
Answered by Conor O'Brien on December 21, 2020
How can lua be so long while all other entries are < 30 bytes... I'm sure even Java would be shorter!
t={}for i=2,...do(i..''):gsub(".",function(d)t[#t+1]=d end)end
table.sort(t)print(1 ..table.concat(t))
t={} -- initialise t as a table
for i=2,... -- iterate from 2 to n
do
(i..''):gsub(".",function(d) -- iterate over each digits in i
t[#t+1]=d -- insert the digit into t
end)
end
table.sort(t) -- sort t
print(1 ..table.concat(t)) -- prepend a 1 to the content of t separated by ''
I'm forced to put a space in print(1 ..
, else it would try to evaluate it to a decimal 1.<decimal part>
, and throws an error because .
isn't a valid decimal part.
Answered by Katenkyo on December 21, 2020
SELECT 1||TRIM(xmlagg(xmlelement(e,c)).EXTRACT('//text()'))FROM(SELECT SUBSTR(s,LEVEL+2,1)c FROM(SELECT MAX(sys_connect_by_path(LEVEL,' '))s FROM DUAL CONNECT BY LEVEL<=:1)CONNECT BY LEVEL<=LENGTH(s)ORDER BY 1);
Un-golfed
SELECT 1||TRIM(xmlagg(xmlelement(e,c)).EXTRACT('//text()')) -- add leading 1, concatenate each char and remove spaces
FROM (
SELECT SUBSTR(s,LEVEL+2,1)c -- split the string in characters, omiting the first number (1)
FROM (
SELECT MAX(sys_connect_by_path(LEVEL,' '))s -- create a string by concatenating numbers
FROM DUAL
CONNECT BY LEVEL<=:1
)
CONNECT BY LEVEL<=LENGTH(s)ORDER BY 1
)
Answered by Jeto on December 21, 2020
Stm`sS1R+
Explanation:
S - range(1,inp+1)
t - ^[1:]
m` - map(str,^)
s - sum(^)
S - sort(^)
1R+ - 1+^
Answered by Blue on December 21, 2020
,Rp@εjS@$+
Explanation:
,Rp@εjS@$+
,Rp@ push range(1, input()+1), pop first element (1), swap
εjS join list on empty string, sort
@$+ prepend the 1
Answered by user45941 on December 21, 2020
1i#x:xe!Ø;$:1+)å(Eh
å'11µ1nran! ¡n~
This pushes 1
to the stack, then stores the input i
into x
(i#x
). Then, a range of all the necessary numbers is created using :xe!Ø;$:1+)å(Eh
, being ended by Ø
, which goes the first i.e. next line. å
takes every number and pushes the digits of that number.
On the next line, å
breaks the last number into its digits, '
sorts the stack, and 11µ
removes 1 1
from the stack. A 1
is then printed, and the numbers are reversed then outputted through the loop an! ¡n
. The program is terminated with ~
.
Answered by Conor O'Brien on December 21, 2020
RDFṢ1œ|Ḍ
RDFṢ1œ|Ḍ Main link. Argument: n (integer)
R Range; yield r := [1, ..., n].
D Convert each k in r into the array of its digits in base 10.
F Flatten the resulting array of lists.
Ṣ Sort the resulting flat list of digits.
1œ| Perform multiset union with 1 as left argument.
This moves a single 1 to the beginning of the list.
Ḍ Convert the resulting list of base 10 to integer.
Answered by Dennis on December 21, 2020
The function s(n) uses a for loop to build up the Champernowne "integer" by converting each number to its string form and concatenating them together. The string is then converted to its equivalent vector of ASCII codes and sorted. The function then swaps any leading zeros with the first one, finally converting the vector back to a string.
To check the function, I put the test cases into a vector vn, then applied s to vn using the vectorize operator. I then check the results against the given test case values.
Mathcad is mathematical application based on 2D worksheets comprised of "regions" each of which can be text, a mathematical expression, program, plot or scripted component.
A mathematical or programming instruction is picked from a palette toolbar or entered using a keyboard shortcut. For golfing purposes, an operation ("byte") is taken to be the number of keyboard operations necessary to create a name or expression (for example, to set the variable a to 3, we would write a:=3. The definition operator := is a single keypress ":", as are a and 3 giving a total of 3 "bytes". The programming for operator requires typing ctl-shft-# (or a single click on the programming toolbar) so again is equivalent to 1 byte.
Answered by Stuart Bruff on December 21, 2020
GJT1-1P
You can run this using:
$ ./gogh noi 'GJT1-1P' <input>
G “ Push a range (1, TOS] ”
J “ Join the TOS ”
T “ Sort the TOS ”
1- “ Remove the first 1 ”
P “ Prepend the TOS to the STOS ”
Answered by Zach Gates on December 21, 2020
Note: This submission uses features that postdate this challenge and is therefore not competitive
Code:
Lß?J{?
Explanation:
L # Creates the list [1 .. input]
ß # Extract the smallest value of the list
? # Print this value (always 1)
J # ''.join(list)
{ # Sort the string
? # Print this value
Uses ISO 8859-1 encoding
Answered by Adnan on December 21, 2020
printf %d 1`seq 2 $1|fold -1|sort`
This builds on the answers of @DigitalTrauma and @OlivierDulac. Try it online with Ideone.
seq 2 $1
prints all integers from 2 to the one specified on the command line.
fold -1
wraps all lines with width 1, i.e., places each character on its own line.
-1
seems to be an undocumented feature.
sort
sorts the characters by their numeric value.
printf %d 1`...`
prepends a 1 to the first line and prints each line as an integer (%d
), with no separation.
This takes advantage of Bash's curious printf implementation, which repeats the format string over and over, until all arguments are consumed.
Answered by Dennis on December 21, 2020
echo 1$(seq 2 $1|sed -e 's/./&n/g'|sort|tr -d \n)
Answered by Olivier Dulac on December 21, 2020
1 .;{,1:.e?}?:1fcbZlL,ZoOlM,10^(L-M)=:Oc.
Takes a number as input.
This solution works with the few changes I made to the built-in Findall predicate f
. OP is apparently OK with using languages older than the answer so I think this is fine (the changes I made were intented a long time ago, I just motivated myself to do it because of this challenge).
1 . § If the input is 1, unify output with 1
; § Else
{ }?:1f § Output a list of all inputs which satisfy
§ the predicate in brackets with the input
§ of the main predicate (ie the input number)
§ as output
,1:.e? § True if the input is an integer between 1
§ and . (the output)
cbZ § Concatenate everything into a single number,
§ remove the first digit (1) and call it Z
lL,ZoOlM, § L is the length of Z, M is the length of O
§ O being Z sorted (which removes the leading
§ 0s)
10^(L-M)=:Oc. § Concatenate 10^(L-M) at the beginning of O
§ and unify it with the output
Answered by Fatalize on December 21, 2020
,u2xεjS'1+
Hex Dump:
2c753278ee6a5327312b
Explanation:
, Read input
u2x Push range from 2..n
εj Join into string
S Sort
'1+ Prepend a "1"
Answered by quintopia on December 21, 2020
Uses current version (7.0.0) of language/compiler.
49[]i:"@YUh]6L)Sh
Inspired by FryTheEgggman's answer.
EDIT (July 29, 2016): You can try it online with some modifications to conform to changes in the language.
>> matl
> 49[]i:"@YUh]6L)Sh
>
> 12
101111223456789
49 % push '1'
[] % push empty array
i: % input "N" and build vector [1, 2, ... N]
" % for each number in this vector
@ % push that number
YU % convert to string
h % concatenate horizontally
] % end
6L) % remove first element
S % sort
h % concatenate horizontally
Answered by Luis Mendo on December 21, 2020
"1"<>ToString/@Sort[Join@@IntegerDigits[2~Range~#]]&
Once again, string processing happened...
Answered by LegionMammal978 on December 21, 2020
^^'LH=^^JB", "-Q"1";+!
I had to add a sorting opcode for this challenge.
^^ ` pop the TOS
' ` read input from the command line
LH ` push a reversed Pythonic range(TOS+1)
=^^J ` remove the top 2 items from the TOS
B ` push the string literal of the TOS
", "- ` remove ", " from the TOS
Q ` sort the TOS
"1";+ ` add "1" to the beginning of the TOS
! ` output the TOS
Answered by Zach Gates on December 21, 2020
An anonymous function. Basically just Rubyfied some of the other answers here..
->n{n>1?(?1+[*2..n].join.chars.sort*'').to_i: n}
Answered by daniero on December 21, 2020
'1',∆[⍋∆←1↓∊⍕¨⍳⎕]
Explanation:
'1',∆[⍋∆←1↓∊⍕¨⍳⎕]
-----------------
⎕ read a number from the keyboard
⍳ get the natural numbers up to and including that number
⍕¨ get the string representation for each number
∊ flatten the array (giving a string of digits)
1↓ remove the first digit (which is always 1)
∆← store the result in ∆
⍋ get a permutation to sort ∆ upwards
∆[ ] rearrange ∆ so that it is sorted
'1', add a 1 to the front
Test:
'1',∆[⍋∆←1↓∊⍕¨⍳⎕]
⎕:
1
1
'1',∆[⍋∆←1↓∊⍕¨⍳⎕]
⎕:
10
10123456789
'1',∆[⍋∆←1↓∊⍕¨⍳⎕]
⎕:
55
10000011111111111111122222222222222223333333333333333444444444444444455555555555566666777778888899999
Answered by marinus on December 21, 2020
As usual in Smalltalk, conceptually very terse, but textually very verbose...
f:l^'1',((2to:l)fold:[:p :q|p asString,q asString])asByteArray sort asString
Add this as a class method for String
and call like this, e.g. for 20, String f: 20
Answered by user15259 on December 21, 2020
#(apply str"1"(sort(apply str(range 2(inc %)))))
Same as all of the others, pretty much. REPL available here.
Answered by MattPutnam on December 21, 2020
P=input();print"1"+"".join(sorted(`range(2,P+1)`)[P*2-4:-2])
Indexing for the win. :-)
P=input();print"1"+"".join(sorted(`range(-P,-1)`))[P*3-5:-2]
Just an alternative.
Answered by Zach Gates on December 21, 2020
Yaaay, first post ever !
Thanks to primo for the 2 bytes save.
print 1,sort"@{[2..<>]}"=~/d/g
As others did, removing 1 and prepending it manually does the work.
Answered by Paul Picard on December 21, 2020
{' '~⍨⍕1,x[⍋x←⍕1↓⍳⍵]}
This is an unnamed monadic function that accepts an integer on the right and returns a string. To call it, assign it to a variable.
Explanation:
x←⍕1↓⍳⍵]} ⍝ Get the numbers 1:input, drop 1, convert to string
x[⍋ ⍝ Sort
⍕1, ⍝ Tack 1 onto the front, flatten to string
{' '~⍨ ⍝ Remove the spaces (side effect of ⍕ on an array)
Answered by Alex A. on December 21, 2020
_="".join;print"1"+_(sorted(_(map(str,range(2,input()+1)))))
Answered by Blue on December 21, 2020
Answered by FryAmTheEggman on December 21, 2020
param($a)(("1"+-join([char[]]-join(2..$a)|sort)),1)[$a-eq1]
Takes input param($a)
and then uses it to index into an array with [$a-eq1]
. If true, we index the second element and output 1
. Otherwise, we concatenate "1"
with the join
ed array created by 1) defining a new range 2..$a
that has been itself join
ed together, 2) casting that as a char-array, and 3) sending it through the Sort-Object
cmdlet, all of which is then output.
Edit1 -- Saved 2 bytes by moving the inner -join
operator.
Answered by AdmBorkBork on December 21, 2020
n->"1"*join(sort([join(2:n)...]))
This is a lambda function that accepts an integer and returns a string. To call it, assign it to a variable.
We construct the range 2:n
, which will be empty for n
< 2, join it into a string, splat the string into an array of characters, sort them, join it into a string, and prepend 1.
Answered by Alex A. on December 21, 2020
Time to show off some new Retina features (it's still not very competitive, but before today this would probably have been closer to 300 bytes).
.+
$0$*1
B
$`
(1)+
$#1
^1|
.
1$0$*1
+r`(1+2) (1+)b
$2 $1
1(1)*
$#1
^
1
While it's possible to convert between decimal and unary quite conveniently now, this is still quite long because I have to convert back and forth several times because some operations are more doable in decimal than in unary and vice-versa.
.+
$0$*1
Let's start by converting the input to unary. This works by matching the input and then using $*1
which repeats 1
that many times (this repetition feature is new as of today).
B
$`
Next, we generate a range from 1
to N
in unary. I've explained why this works in my FizzBuzz answer.
(1)+
$#1
We convert each number in the range back to decimal so we can work with the decimal digits. This is done by matching each of the unary numbers such that each 1
generates a separate capture. Then we replace that with the number of captures of group one, using the new capture count syntax $#1
.
^1|
This removes the leading 1
as well as all spaces from the string so we're left with only the digits (except for a single 1
).
.
1$0$*1
We convert back to unary and add 1
to each digit (to ensure that even 0
is a non-empty). We also insert a space in front of each digit to ensure that they are separated.
+r`(1+2) (1+)b
$2 $1
We repeatedly match a small number preceded by a larger number and swap them. That's bubble sort in Retina. :)
1(1)*
$#1
Aaaand back to decimal.
^
1
Finally, we insert a single 1
at the front to account for the one we've removed earlier.
Answered by Martin Ender on December 21, 2020
Saved 3 bytes thanks to edc65
x=>eval("for(b='';x>1;)1+[...b+=x--].sort().join``")
Builds a string of all numbers from 2 to x
, then splits, sorts, joins, and adds a 1 to the beginning. This may still be golfable; suggestions welcome!
Answered by ETHproductions on December 21, 2020
Answered by Digital Trauma on December 21, 2020
import Data.List
f n='1':sort(show=<<[2..n])
Unfortunately sort
is in Data.List
, that's 17 bytes!
Answered by nimi on December 21, 2020
1+2o°U ¬¬n ¬
1+2o°U ¬¬n ¬ // Implicit: U = input integer
2o°U // Generate the range of integers from 2 to U, inclusive.
¬¬ // Join, then split into chars.
n // Sort.
1+ ¬ // Join again, and add a 1 to the beginning.
// Implicit: output last expression
Answered by ETHproductions on December 21, 2020
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