Astronomy Asked by SE - stop firing the good guys on February 9, 2021
Between a moon and the primary, the equation for tidal heating is:
$$dot E_mathit{Tidal} = – Im(k_2) frac{21}{2} frac{GM_h^2 R^5 n e^2}{a^6}$$
But how does one calculate the tidal heating between moons?
Simplifying assumptions I’m fine with:
While I’m not able to come up with any formula, I suspect the following properties hold:
This is for instance the case for the Saturn moons Enceladus and Dione.
This is not the case for Enceladus and Dione. Enceladus's orbit about Saturn has an eccentricity of 0.0047, which while low, is more than enough to result in tidal heating. Dione does play a role in the tidal heating of Enceladus, but that role is secondary. Dione is what keeps Enceladus's eccentricity non-zero via Enceladus's 2:1 mean motion orbital resonance with Dione.
Answered by David Hammen on February 9, 2021
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