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I'm sure this seems like a Google question, but I've BTDT and come up empty. The problem I'm trying to solve is to obtain cables that are as "leak proof"...
Asked on 09/27/2021 by user103218
2 answerWhen designing a waveform for packet radio usage, it'd be helpful to know a few things, mainly distribution of coherency bandwidthsdistribution of coherency timesWhilst such statistics are reasonably possible to...
Asked on 09/27/2021 by Marcus Müller
2 answerI am an electrical engineer working on a product that needs a loopstick antenna. I had thought that AM radios were so commoditized that I'd be able to find an...
Asked on 09/27/2021
1 answerSee the unconventional antenna shown below, The whole antenna is made of two mirror-imaged Alum metal stampings on either side of a 2-cm hollow 31-cm long rectangular plastic boom. The...
Asked on 09/27/2021 by Roe
1 answerI have been trying to create a low cost communication setup for when I go hunting. Using this setup the hope is to be able to talk to one...
Asked on 09/27/2021 by Layne Hedrick
1 answerI'm building a Double Cross Dipole antenna for 437 MHz to be used with a SDR receiver for CW cubesat.The idea is to follow this "classic"...
Asked on 09/27/2021 by Carlo IU2KQB
1 answerI've build a trap dipole for 20/40m bands. Traps are made of a coil wound on an insulator of RG213 coax and 3 kV NP0 capacitors. The impedance measured with...
Asked on 09/27/2021 by Aleksander Alekseev - R2AUK
3 answerI want to measure quartz crystal motional parameters with a VNA. Unfortunately all Google searches I've done have lead me to nothing in concrete. I know how to get an...
Asked on 09/27/2021 by S.s.
2 answerI was searching for 1:1 balun designs that would be efficient at VHF yet could easily be made from commonly available materials when I came across these two: ...
Asked on 09/27/2021 by Ivan R2AZR
2 answerI searched and couldn't find a direct answer so thought I'd ask. We all know the mantra "traps aren't good as they have losses", but how much loss are we...
Asked on 09/27/2021
2 answerGet help from others!
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